发布时间：2023-12-25 来源：win7旗舰版 浏览量：
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网络技术是从1990年代中期发展起来的新技术，它把互联网上分散的资源融为有机整体，实现资源的全面共享和有机协作，使人们能够透明地使用资源的整体能力并按需获取信息。资源包括高性能计算机、存储资源、数据资源、信息资源、知识资源、专家资源、大型数据库、网络、传感器等。 当前的互联网只限于信息共享，网络则被认为是互联网发展的第三阶段。 tombkeeper (t0mbkeeper_at_hotmail.com) /* MSNMessenger的口令是经过DPAPI加密后保存在注册表中的 * 这个程序演示解码过程 * tombkeeper[0x40]nsfocus[0x2e]com * tombkeeper[0x40]xfocus[0x2e]net * 2004.08.11 */#include <Windows.h> #pragma comment(lib, "Advapi32.lib")#define FCHK(a) if (!(a)) {printf(#a " failed\n"); return 0;}typedef struct _CRYPTOAPI_BLOB { DWORD cbData; BYTE* pbData; } DATA_BLOB;typedef struct _CRYPTPROTECT_PROMPTSTRUCT { DWORD cbSize; DWORD dwPromptFlags; HWND hwndApp; LPCWSTR szPrompt; } CRYPTPROTECT_PROMPTSTRUCT, *PCRYPTPROTECT_PROMPTSTRUCT;typedef BOOL (WINAPI *PCryptUnprotectData)( DATA_BLOB* pDataIn, LPWSTR* ppszDataDescr, DATA_BLOB* pOptionalEntropy, PVOID pvReserved, CRYPTPROTECT_PROMPTSTRUCT* pPromptStruct, DWORD dwFlags, DATA_BLOB* pDataOut );PCryptUnprotectData CryptUnprotectData = NULL; int main(void) { int ret; HMODULE hNtdll;HKEY hKey; DWORD dwType; char Data[0x100] = {0}; DWORD dwSize;DATA_BLOB DataIn; DATA_BLOB DataOut;ret = RegOpenKeyEx ( HKEY_CURRENT_USER, "Software\\Microsoft\\MSNMessenger", 0, KEY_READ, &hKey ); if( ret != ERROR_SUCCESS ) return 1;ret = RegQueryValueEx ( hKey, "Password.NET Messenger Service", NULL, &dwType, Data, &dwSize ); if( ret != ERROR_SUCCESS ) return 1;FCHK ((hNtdll = LoadLibrary ("Crypt32.dll")) != NULL); FCHK ((CryptUnprotectData = (PCryptUnprotectData) GetProcAddress (hNtdll, "CryptUnprotectData")) != NULL);DataIn.pbData = Data + 2; //口令密文从第二位开始 DataIn.cbData = dwSize-2;CryptUnprotectData ( &DataIn, NULL, NULL, NULL, NULL, 1, &DataOut );base64_decode (DataOut.pbData, Data, strlen(DataOut.pbData)); printf ( "MSN Password: %s\n", Data); return 0; }//copied from GNU libc - libc/resolv/base64.c int base64_decode (char const *src, char *target, size_t targsize) { static const char Base64[] = "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/"; static const char Pad64 = '=';int tarindex, state, ch; char *pos;state = 0; tarindex = 0;while ((ch = *src++) != '\0') { if (isspace (ch)) /* Skip whitespace anywhere. */ continue;if (ch == Pad64) break;pos = strchr (Base64, ch); if (pos == 0) /* A non-base64 character. */ return (-1);switch (state) { case 0: if (target) { if ((size_t) tarindex >= targsize) return (-1); target[tarindex] = (pos - Base64) << 2; } state = 1; break; case 1: if (target) { if ((size_t) tarindex + 1 >= targsize) return (-1); target[tarindex] |= (pos - Base64) >> 4; target[tarindex + 1] = ((pos - Base64) & 0x0f) << 4; } tarindex++; state = 2; break; case 2: if (target) { if ((size_t) tarindex + 1 >= targsize) return (-1); target[tarindex] |= (pos - Base64) >> 2; target[tarindex + 1] = ((pos - Base64) & 0x03) << 6; } tarindex++; state = 3; break; case 3: if (target) { if ((size_t) tarindex >= targsize) return (-1); target[tarindex] |= (pos - Base64); } tarindex++; state = 0; break; default: abort (); } }/* * We are done decoding Base-64 chars. Let's see if we ended * on a byte boundary, and/or with erroneous trailing characters. */if (ch == Pad64) { /* We got a pad char. */ ch = *src++; /* Skip it, get next. */ switch (state) { case 0: /* Invalid = in first position */ case 1: /* Invalid = in second position */ return (-1);case 2: /* Valid, means one byte of info */ /* Skip any number of spaces. */ for ((void) NULL; ch != '\0'; ch = *src++) if (!isspace (ch)) break; /* Make sure there is another trailing = sign. */ if (ch != Pad64) return (-1); ch = *src++; /* Skip the = */ /* Fall through to "single trailing =" case. */ /* FALLTHROUGH */case 3: /* Valid, means two bytes of info */ /* * We know this char is an =. Is there anything but * whitespace after it? */ for ((void) NULL; ch != '\0'; ch = *src++) if (!isspace (ch)) return (-1);/* * Now make sure for cases 2 and 3 that the "extra" * bits that slopped past the last full byte were * zeros. If we don't check them, they become a * subliminal channel. */ if (target && target[tarindex] != 0) return (-1); } } else { /* * We ended by seeing the end of the string. Make sure we * have no partial bytes lying around. */ if (state != 0) return (-1); }return (tarindex); } 网络的神奇作用吸引着越来越多的用户加入其中，正因如此，网络的承受能力也面临着越来越严峻的考验―从硬件上、软件上、所用标准上......，各项技术都需要适时应势，对应发展，这正是网络迅速走向进步的催化剂。 |
tombkeeper (t0mbkeeper_at_hotmail.com) /* MSNMess
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